# How do you find the local extrema for #y=sqrtx/(x-5)#?

##### 1 Answer

There is none.

#### Explanation:

First find the derivative and set the derivative equal to 0:

Using the **quotient rule.**

We now need to find the roots of this equation:

But there is a problem in finding the

Notice that we would have to take the square root of a negative so we do not have a value for

graph{sqrt(x)/(x-5) [-10, 10, -5, 5]}

As a result of the above and a quick look at the graph we can see that there are no turning points and as such there are no local extrema.